Question:medium

The temperature of a metal strip having coefficient of linear expansion $\alpha$ is increased from $T_1$ to $T_2$ resulting in increase of its length by $\Delta L_1$. The temperature is further increased from $T_2$ to $T_3$ such that the increase in its length is $\Delta L_2$.
Given $T_3 + T_1 = 2T_2$ and $T_2 - T_1 = \Delta T$, the value of $\Delta L_2$ is ________.

Updated On: Apr 10, 2026
  • $\Delta L_1 [1 + 2\alpha^2(\Delta T)^2]$
  • $\Delta L_1 [1 + \alpha^2(\Delta T)^2]$
  • $\Delta L_1 [1 + 2\alpha\Delta T]$
  • $\Delta L_1 [1 + \alpha\Delta T]$
Show Solution

The Correct Option is D

Solution and Explanation

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