Question

The susceptibility of a paramagnetic material is \(99\). The permeability of the material in Wb/A-m, is 
[Permeability of free space \(μ_0\) = \(4π × 10^{–7}\) Wb/A-m]

• A. \(4π × 10^{–7}\)
• B. \(4π × 10^{–4}\)
• C. \(4π × 10^{–5}\)
• D. \(4π × 10^{–6}\)

Answer 1

The Correct Option is C

 To find the permeability of the paramagnetic material, we need to use the relationship between susceptibility (\( \chi \)) and permeability (\( \mu \)). For a paramagnetic material, the relationship is given by:

\(\mu = \mu_0 (1 + \chi)\)

where:

• \(\mu_0\) is the permeability of free space, \(\mu_0 = 4\pi \times 10^{-7}\) Wb/A-m
• \(\chi\) is the susceptibility of the material, given as \(99\)

Substituting the given values into the formula, we get:

\(\mu = 4\pi \times 10^{-7} \times (1 + 99)\)

Calculating inside the brackets gives:

\((1 + 99) = 100\)

Thus, substitute back into the equation:

\(\mu = 4\pi \times 10^{-7} \times 100\)

\(\mu = 4\pi \times 10^{-5}\)

Thus, the permeability of the material is \(4\pi \times 10^{-5}\) Wb/A-m.

The correct option is \(4\pi \times 10^{-5}\).