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The surface tension of a soap solution is \(3.5 \times 10^{-2}\) N/m. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is \(\alpha \times 10^{-6}\) J. The value of \(\alpha\) is ______. (\(\pi = 22/7\))
The surface tension of a soap solution is \(3.5 \times 10^{-2}\) N/m. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is \(\alpha \times 10^{-6}\) J. The value of \(\alpha\) is ______. (\(\pi = 22/7\))
Updated On: Apr 10, 2026
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Correct Answer: 264
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