Question:medium

The standard reduction potential at 25°C for \( MnO_4^- / H^+ \) is \( +1.49 \, \text{V} \).

The given standard reduction potentials are:

  • \( Co^{3+}/Co^{2+} = +1.81 \, \text{V} \)
  • \( Cr^{3+}/Cr = -0.74 \, \text{V} \)
  • \( Au^{3+}/Au = +1.50 \, \text{V} \)
  • \( Ag^+/Ag = +0.80 \, \text{V} \)

We need to identify which species cannot be oxidized by \( MnO_4^- / H^+ \).

Concept: A species will be oxidized by \( MnO_4^- \) only if its reduction potential is less than \( +1.49 \, \text{V} \).

Thus, species with higher reduction potential than \( MnO_4^- \) cannot be oxidized.

Comparing values:

  • \( Co^{3+}/Co^{2+} = +1.81 \, \text{V} \) → cannot be oxidized
  • \( Au^{3+}/Au = +1.50 \, \text{V} \) → cannot be oxidized

Final Answer: \( Co^{3+}/Co^{2+} \) and \( Au^{3+}/Au \)

Show Hint

The ability of a substance to be oxidized depends on the relative reduction potentials. The lower the reduction potential, the easier it is to oxidize the substance.
Updated On: May 5, 2026
  • a & d
  • a & c
  • b & c
  • b & d
Show Solution

The Correct Option is B

Solution and Explanation

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