Question:medium

The speed with which the earth have to rotate on its axis so that a person on the equator would weigh \((3/5)^{\text{th}\) as much as present. (Radius of earth = 6400 km)}

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At equator, centripetal acceleration reduces effective weight. At poles, weight = mg.
Updated On: Apr 23, 2026
  • \(4.83 \times 10^{-3}\) rad s\(^{-1}\)
  • \(5.41 \times 10^{-3}\) rad s\(^{-1}\)
  • \(7.82 \times 10^{-4}\) rad s\(^{-1}\)
  • \(8.88 \times 10^{-14}\) rad s\(^{-1}\)
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The Correct Option is C

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