Question:medium
The solubility product constants of \(Ag_2CrO_4\) and \(AgBr\) are \(32x\) and \(4y\) respectively at 298 K. The value of}
\[
\left(\frac{\text{molarity of } Ag_2CrO_4}{\text{molarity of } AgBr}\right)
\]
can be expressed as:
The solubility product constants of \(Ag_2CrO_4\) and \(AgBr\) are \(32x\) and \(4y\) respectively at 298 K. The value of}
\[
\left(\frac{\text{molarity of } Ag_2CrO_4}{\text{molarity of } AgBr}\right)
\]
can be expressed as:
Updated On: Apr 10, 2026
- \(\dfrac{2\sqrt[3]{x}}{y}\)
- \(2\sqrt{\dfrac{x}{y}}\)
- \(\sqrt{\dfrac{x}{y}}\)
- \(\dfrac{\sqrt[3]{x}}{\sqrt{y}}\)
Show Solution
The Correct Option is B
Solution and Explanation
Was this answer helpful?
0
Top Questions on Solubility products
- Correct solubility order of AgF, AgCl, AgBr, AgI in water is:
- WBJEE - 2024
- Chemistry
- Solubility products
- Which of the following statement(s) is/are correct?
- WBJEE - 2024
- Chemistry
- Solubility products
- The molar solubility(s) of zirconium phosphate with molecular formula \( \text{Zr}^{4+} \text{PO}_4^{3-} \) is given by relation:
- JEE Main - 2025
- Chemistry
- Solubility products
- Ksp for \( \text{Cr(OH)}_3 \) is \( 1.6 \times 10^{-30} \). What is the molar solubility of this salt in water?
- JEE Main - 2025
- Chemistry
- Solubility products
- Want to practice more? Try solving extra ecology questions todayView All Questions
