The shortest distance between the lines \(\frac{x-3}{-1} = \frac{y-2}{4} = \frac{z-1}{2}\) and \(\frac{x-1}{2} = \frac{y-1}{1} = \frac{z-2}{5}\) is:
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When calculating \(\vec{b}_1 \times \vec{b}_2\), you can factor out common terms (like 9 here) to simplify the magnitude and dot product calculations, as long as you account for it in the final division.