Question:medium
If $\vec{a}_R = \tan \theta_R \hat{i} + \hat{j}$ and $\vec{b}_R = \hat{i} - \cot \theta_R \hat{k}$ where $\theta_R = \frac{2^{R-1} \pi}{2^N + 1}$, then the value of $\frac{\sum_{R=1}^N |\vec{a}_R|^2}{\sum_{R=1}^N |\vec{b}_R|^2}$ is
If $\vec{a}_R = \tan \theta_R \hat{i} + \hat{j}$ and $\vec{b}_R = \hat{i} - \cot \theta_R \hat{k}$ where $\theta_R = \frac{2^{R-1} \pi}{2^N + 1}$, then the value of $\frac{\sum_{R=1}^N |\vec{a}_R|^2}{\sum_{R=1}^N |\vec{b}_R|^2}$ is
Updated On: Apr 4, 2026
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