Let a hyperbola be \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) and ellipse be \(\frac{x^2}{9} + \frac{y^2}{8} = 1\). If length of latus rectum of hyperbola is equal to minor axis of ellipse and eccentricity of hyperbola is equal to semi-major axis of ellipse, then \(2ae\) is equal to (where 'e' is the eccentricity of hyperbola)
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For an ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), the semi-major axis is $a$ and the minor axis length is $2b$. Always be careful to distinguish between 'semi-axis' and 'axis length'.