To solve this problem, we need to understand the behavior of the light in the context of the prism with a silvered surface. Here are the step-by-step details:
- First, recognize that the refractive index of the prism material is given as \sqrt{2}, and the prism angle is 30^\circ.
- When a beam of light enters the prism, it refracts at the first surface. It then internally reflects off the silvered surface, which acts like a mirror.
- The light beam would retrace its path if, after reflection, it strikes the original surface at the same angle it was incident.
- Using the principle of reversibility of light, we know for the light to retrace its path, the angle of reflection at the silvered surface should be such that the angle of incidence at the first surface equals the angle of refraction back into the prism.
- The condition for retracing the path leads us to the angle of incidence at the first prism face being equal to the angle of refraction upon re-entering into the same medium.
To find the angle at which the light should enter the prism, consider the geometry and laws of refraction:
- Since only one surface of the prism is silvered, the prism effectively behaves like a right-angle prism for an observing eye.
- The refraction law is given by n \sin i = \sin r,
where n is the refractive index, i is the angle of incidence, and r is the angle of refraction.
For this problem:
- When the angle of prism is 30^\circ and the refractive index \sqrt{2}, we need the angle i such that the internal angle at the silvered surface leads to the light retracing the path.
- For the given setup, the angle of incidence i is calculated to be 45^\circ using Snell's law and the geometric principles of light reflecting back along its own path due to the mirror surface.
Therefore, the correct answer is 45^\circ, making the angle of incidence required to retrace its path upon reflection 45^\circ.