Question:medium

The ratio of the energy released when \(2.5\times10^{21}\) atoms of uranium undergo nuclear fission and the energy equivalent of \(2\,\mathrm{mg}\) mass of uranium is nearly \[ \text{(Average energy released per fission of uranium nucleus }=200\,\mathrm{MeV}) \]

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Useful relations: \[ \boxed{ E_{\text{fission}}=N\times200\,\mathrm{MeV} } \] and \[ \boxed{ E=mc^2. } \]
Updated On: Jul 15, 2026
  • \(4:5\)
  • \(8:9\)
  • \(4:9\)
  • \(2:3\)
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The Correct Option is C

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