Question:easy

The range of strong nuclear force is in the order of:

Show Hint

Remember the order of ranges for fundamental forces:

Gravitational Force: Infinite range

Electromagnetic Force: Infinite range

Strong Nuclear Force: Short range ($\sim 10^{-15}\text{ m}$ or $1\text{ fm}$)

Weak Nuclear Force: Ultra-short range ($\sim 10^{-18}\text{ m}$)
Updated On: Jun 10, 2026
  • Infinity
  • $\sim 10^{-16}\text{ m}$
  • Zero
  • $\sim 10^{-15}\text{ m}$
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Know the four basic forces.
Nature has four fundamental forces. They are gravity, the electromagnetic force, the weak nuclear force and the strong nuclear force. Each one acts over its own special distance. Some reach very far, while others act only over tiny distances.

Step 2: Focus on the strong nuclear force.
The strong nuclear force is the glue that holds protons and neutrons together inside the nucleus of an atom. Without it, the positive protons would push each other apart and the nucleus would break.

Step 3: Compare it with gravity and the electric force.
Gravity and the electric force never fully stop. They get weaker as distance grows, but they still reach out to infinity. The strong force is different. It is felt only when two nucleons are extremely close.

Step 4: Recall the size of a nucleus.
A nucleus is incredibly small. Its size is measured in femtometres, where $1\text{ fm} = 10^{-15}\text{ m}$. The nucleons inside sit only about one femtometre apart from each other.

Step 5: Match the range to the size of the nucleus.
Since the strong force must bind nucleons that are about one femtometre apart, its range must also be about one femtometre. Beyond this tiny distance the force quickly fades to almost nothing. So its range is of the order of: \[ \sim 10^{-15}\text{ m} \]

Step 6: Reject the wrong choices.
The range is not infinity, because the force dies out very fast outside the nucleus. It is not zero, because the force truly exists and binds the nucleus. It is not $10^{-16}\text{ m}$, which is far smaller than the actual nucleus. The correct order of magnitude is one femtometre. \[ \boxed{\sim 10^{-15}\text{ m}} \]
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