Step 1: Find each mixture's alcohol fraction.
Container A is alcohol to water 5:3, so its alcohol fraction is $\dfrac{5}{8}$. Container B is 1:3, so its alcohol fraction is $\dfrac{1}{4}$. The target blend must be half alcohol, fraction $\dfrac{1}{2}$.
Step 2: Set up the unknown amounts.
Let $a$ litres come from A and $b$ litres from B, with $a + b = 2.1$ litres of final liquid.
Step 3: Write the alcohol balance.
Total alcohol must be half of 2.1, namely 1.05 litres: $\dfrac{5}{8}a + \dfrac{1}{4}b = 1.05$.
Step 4: Substitute $b = 2.1 - a$.
$\dfrac{5}{8}a + \dfrac{1}{4}(2.1 - a) = 1.05$. This gives $\dfrac{5}{8}a + 0.525 - 0.25a = 1.05$.
Step 5: Solve for $a$.
$\left(0.625 - 0.25\right)a = 1.05 - 0.525$, so $0.375a = 0.525$ and $a = \dfrac{0.525}{0.375} = 1.4$.
Step 6: Verify the mix.
Then $b = 2.1 - 1.4 = 0.7$. Alcohol $= \dfrac{5}{8}(1.4) + \dfrac{1}{4}(0.7) = 0.875 + 0.175 = 1.05$, exactly half. So draw 1.4 litres from A, matching option 1.
\[ \boxed{1.4} \]