Question:medium

The radical centre of the system of circles, \[ x^2 + y^2 + 4x + 7 = 0,\quad 2(x^2 + y^2) + 3x + 5y + 9 = 0 \] and \(x^2 + y^2 + y = 0\) is

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Radical center = solve pairwise subtractions of circle equations.

Updated On: Apr 16, 2026

\((-2,-1)\)
\((1,-2)\)
\((-1,-2)\)
None of these

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The Correct Option is A

Solution and Explanation

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The radical centre of the system of circles, \[ x^2 + y^2 + 4x + 7 = 0,\quad 2(x^2 + y^2) + 3x + 5y + 9 = 0 \] and \(x^2 + y^2 + y = 0\) is

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The Correct Option is A

Solution and Explanation

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