Question:medium

The quantity of $\text{Ca}$ that can be produced from molten $\text{CaCl}_2$, with the same quantity of electricity (in coulombs) required to produce $8\text{ g}$ of $\text{Mg}$ from molten $\text{MgCl}_2$ is: [Atomic mass of $\text{Mg} = 24\text{ u}$; Atomic mass of $\text{Ca} = 40\text{ u}$]}

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Since both $\text{Ca}^{2+}$ and $\text{Mg}^{2+}$ share the exact same charge valency ($z=2$), the number of moles of each metal produced by a given quantity of electricity will be identical. $4.8\text{ g}$ of $\text{Mg}$ corresponds to $\frac{4.8}{24} = 0.2\text{ moles}$. Therefore, you will get exactly $0.2\text{ moles}$ of calcium: $0.2 \times 40 = 8.0\text{ g}$ immediately!
Updated On: May 16, 2026
  • $5.2\text{ g}$
  • $4.8\text{ g}$
  • $6.0\text{ g}$
  • $8.0\text{ g}$
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The Correct Option is D

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