Question:medium
The product B formed in the following reaction sequence is:
\[
{C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B)
\]
The product B formed in the following reaction sequence is:
\[
{C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B)
\]
Show Hint
For nucleophilic substitution reactions, always identify the intermediate and use the correct reagents for further transformations.
Updated On: Aug 8, 2026
Show Solution
The Correct Option is C
Solution and Explanation
To determine product B from the given reaction sequence, each step must be analyzed:
- Step 1: Hydrolysis of Benzonitrile
Benzonitrile (\({C}_6{H}_5{CN}\)) is subjected to hydrolysis with hydrochloric acid (HCl). This converts it to benzamide (\({C}_6{H}_5{CONH}_2\)). The reaction is:
\[ {C}_6{H}_5{CN} + 2H_2O + HCl \rightarrow {C}_6{H}_5{CONH}_2 + NH_4Cl \]
- Step 2: Reaction with Silver Cyanide
Benzamide (Product A) reacts with silver cyanide (AgCN). A nucleophilic substitution occurs, transforming the amide group into an isocyanate group, yielding phenyl isocyanate (\({C}_6{H}_5{NCO}\)). The reaction is:
\[ {C}_6{H}_5{CONH}_2 + AgCN \rightarrow {C}_6{H}_5{NCO} + Ag \]
The final product, B, is phenyl isocyanate (\({C}_6{H}_5{NCO}\)).
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