Question:medium

The point on the straight line \(y = 2x + 11\) which is nearest to the circle \(16(x^2 + y^2) + 32x - 8y - 50 = 0\), is

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Nearest point from a line to a circle is always the foot of perpendicular from the center to the line.

Updated On: Apr 16, 2026

\(\left(\frac{9}{2},2\right)\)
\(\left(\frac{9}{2},-2\right)\)
\(\left(-\frac{9}{2},2\right)\)
\(\left(-\frac{9}{2},-2\right)\)

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The Correct Option is C

Solution and Explanation

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The point on the straight line \(y = 2x + 11\) which is nearest to the circle \(16(x^2 + y^2) + 32x - 8y - 50 = 0\), is

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The Correct Option is C

Solution and Explanation

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