The point of intersection of the lines $3x + 2y = 6$ and $3x - 2y = -2$ is:

Question

Given that $ \cot \left( \frac{A+B}{2} \right) \cdot \tan \left( \frac{A-B}{2} \right) = $, and the equation $ \frac{x}{2} + \frac{y}{3} + \frac{2}{6} - 1 = 0 $, find the area of $ \Delta ABC = 2 $.

Answer 1

Step 1: Add equations \[ (3x + 2y) + (3x - 2y) = 6 - 2 \] \[ 6x = 4 \Rightarrow x = \frac{2}{3} \]

Step 2: Substitute \[ 3\left(\frac{2}{3}\right) + 2y = 6 \] \[ 2 + 2y = 6 \Rightarrow 2y = 4 \Rightarrow y = 2 \] \[ {\left(\frac{2}{3}, 2\right)} \]

Economic System	Characteristics
a. Capitalism	i. Private ownership of resources; market-driven economy with minimal government intervention
b. Socialism	ii. Government ownership of key industries; centralized economic planning
c. Mixed Economy	iii. Combination of private and government ownership; focus on social welfare and regulation
d. Market Economy	iv. Private ownership with some government regulation; competition and market forces determine economic outcomes

The point of intersection of the lines $3x + 2y = 6$ and $3x - 2y = -2$ is:

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The Correct Option is A

Solution and Explanation

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