Question

The order of relative bond strength of oxygen molecule, superoxide ion and peroxide ion is

• A. $\mathrm{O}_2<\mathrm{O}_2^-<\mathrm{O}_2^{2-}$
• B. $\mathrm{O}_2>\mathrm{O}_2^->\mathrm{O}_2^{2-}$
• C. $\mathrm{O}_2<\mathrm{O}_2^->\mathrm{O}_2^{2-}$
• D. $\mathrm{O}_2>\mathrm{O}_2^-<\mathrm{O}_2^{2-}$

Hint:

Higher bond order means stronger bond.

Answer 1

The Correct Option is B

Step 1: Conceptual Understanding:
Bond order determines bond strength.
Step 2: Explanation in Detail:
Bond order: $\mathrm{O_2}$ (2), $\mathrm{O_2^-}$ (1.5), $\mathrm{O_2^{2-}}$ (1). Bond strength decreases with bond order.
Step 3: Therefore, Stating the Final Answer
$\mathrm{O}_2>\mathrm{O}_2^->\mathrm{O}_2^{2-}$.