(p ∨ q) ∧ (p ∨ r) ⇒ (q ∨ r) is true if either (p ∨ q) ∧ (p ∨ r) is false or (q ∨ r) is true. We analyze all possible truth values of p, q, r to find the number of ordered triplets:
Total true triplets:
| (0,0,0) | (0,1,0) | (1,1,0) | |
| (0,0,1) | (1,0,1) | (0,1,1) | (1,1,1) |
Seven triplets satisfy the condition.