Question:medium

The number of numbers, strictly between 5000 and 10000 can be formed using the digits 1,3,5,7,9 without repetition, is

Updated On: Mar 30, 2026
  • 72
  • 120

  • 6

  • 12

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The Correct Option is A

Solution and Explanation

To determine how many numbers can be formed using the digits 1, 3, 5, 7, and 9 that are strictly between 5000 and 10000, and without repeating the digits, follow the steps below:

  1. Understanding the Range: We need numbers between 5000 and 10000, which means they must be four-digit numbers starting with the digit 5, 7, or 9, as these are the only digits greater than or equal to 5 that we can use.
  2. Counting Numbers Starting with Each Valid First Digit:
    • Numbers starting with 5:
      • If 5 is the first digit, the remaining digits (1, 3, 7, 9) can be arranged in the other three places.
      • There are 4 options for the second digit, 3 options for the third, and 2 options for the fourth digit.
      • The number of such arrangements is calculated as: \(4 \times 3 \times 2 = 24\).
    • Numbers starting with 7:
      • If 7 is the first digit, the remaining digits (1, 3, 5, 9) can be arranged in the other three places.
      • There are 4 options for the second digit, 3 options for the third, and 2 options for the fourth digit.
      • The number of such arrangements is: \(4 \times 3 \times 2 = 24\).
    • Numbers starting with 9:
      • If 9 is the first digit, the remaining digits (1, 3, 5, 7) can be arranged in the other three places.
      • There are 4 options for the second digit, 3 options for the third, and 2 options for the fourth digit.
      • The number of such arrangements is: \(4 \times 3 \times 2 = 24\).
  3. Adding Up the Possibilities: The total number of numbers that meet the criteria is the sum of the possibilities for each starting digit:
    • \(24 + 24 + 24 = 72\)
  4. Conclusion: Hence, the number of numbers strictly between 5000 and 10000 that can be formed using the digits 1, 3, 5, 7, and 9 without repetition is 72.
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