Question:hard

The number of metal-metal bonds present in \(Ir_4(CO)_{12}\) is:

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A tetrahedral M4 cluster has six edges, one metal-metal bond per edge.
Updated On: Jul 3, 2026
  • 3
  • 4
  • 5
  • 6
Show Solution

The Correct Option is D

Solution and Explanation

Electron counting: 4 Ir(9e)=36, 12 CO(2e)=24, total 60. 4x18-2n=60 => n=6 M-M bonds, matching tetrahedron edges.
\[\boxed{6}\]
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