Question:medium
The number of lone pairs of electrons on the central atom of $\text{XeO}_3, \text{XeOF}_4$ and $\text{XeF}_6$ respectively is
The number of lone pairs of electrons on the central atom of $\text{XeO}_3, \text{XeOF}_4$ and $\text{XeF}_6$ respectively is
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A general formula for the number of lone pairs (LP) on the central atom is: $LP = \frac{1}{2} [\text{Valence } e^- \text{ on central atom} + (\text{number of attached atoms} \times \text{valency}) - 2 \times \text{charge}]$. A simpler way is: $LP = \frac{1}{2} [\text{Valence } e^- - \text{Bonding } e^-]$. For $\text{O}$, count 2 bonding $e^-$.
Updated On: Mar 30, 2026
- 1, 1, 1
- 3, 2, 1
- 2, 1, 0
- 1, 2, 1
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The Correct Option is A
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