The number of \(\theta \in(0,4 \pi) \)for which the system of linear equations \(3(\sin 3 \theta) x-y+z=2\) \(3(\cos 2 \theta) x+4 y+3 z=3\) \(6 x+7 y+7 z=9\) has no solution is :
To solve this problem, we need to determine the number of values of \(\theta \in(0,4 \pi) \) for which the given system of linear equations has no solution:
Thus, there are 7 values of \(\theta\) for which the system of equations has no solution.
Let \[ A = \{x : |x^2 - 10| \le 6\} \quad \text{and} \quad B = \{x : |x - 2| > 1\}. \] Then