Question:medium
The normal at the point (3, 4) on a circle cuts the circle at the point (-1, -2). Then the equation of the circle is
The normal at the point (3, 4) on a circle cuts the circle at the point (-1, -2). Then the equation of the circle is
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Diameter ends give circle equation: \((x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0\).
Updated On: Apr 7, 2026
- \(x^2 + y^2 + 2x - 2y - 13 = 0\)
- \(x^2 + y^2 - 2x - 2y - 11 = 0\)
- \(x^2 + y^2 - 2x + 2y + 12 = 0\)
- \(x^2 + y^2 - 2x - 2y + 14 = 0\)
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The Correct Option is B
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