Question:easy

The minimum energy gap of a semi-conductor used in manufacturing LED is

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Visible light starts around Red, which corresponds to $1.8\text{ eV}$. Any band gap smaller than this drops into invisible infrared territory.
Updated On: Jun 3, 2026
  • 3 eV
  • 3.6 eV
  • 2.8 eV
  • 1.8 eV
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The Correct Option is D

Solution and Explanation

Step 1: How an LED makes light.
In an LED, electrons fall across the band gap and give out photons. The photon energy equals the band gap $E_{g}$.

Step 2: Visible light energy range.
Visible light photons have energy from about $1.8$ eV (red) to $3.0$ eV (violet).

Step 3: The lowest needed band gap.
To just make visible (red) light, the band gap must be at least the red-light value, about $1.8$ eV.

Step 4: Why small-gap materials fail.
Silicon ($1.1$ eV) and germanium ($0.7$ eV) have small gaps, so they give invisible infrared light.

Step 5: Materials that work.
Compounds like GaAsP are made with a gap of about $1.8$ eV so they shine visible light.

Step 6: Pick the answer.
So the minimum band gap for an LED's visible light is $1.8$ eV, which is option 4.
\[ \boxed{E_{g} = 1.8 \text{ eV}} \]
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