Question:medium

The maximum value of \(3\cos\theta+4\sin\theta\) is

Show Hint

The maximum value of \(a\cos x+b\sin x\) is \(\sqrt{a^2+b^2}\).
  • \(2\)
  • \(4\)
  • \(5\)
  • \(1\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
This question asks for the maximum value of a linear combination of sine and cosine functions of the form $a \cos\theta + b \sin\theta$.
Step 2: Key Formula or Approach:
For an expression of the form $f(\theta) = a \cos\theta + b \sin\theta$, the range of values is given by: \[ -\sqrt{a^2 + b^2} \le a \cos\theta + b \sin\theta \le \sqrt{a^2 + b^2} \] Therefore, the maximum value is $\sqrt{a^2 + b^2}$ and the minimum value is $-\sqrt{a^2 + b^2}$.
Step 3: Detailed Explanation:
In the given expression, $3 \cos\theta + 4 \sin\theta$, we have: \[ a = 3 \] \[ b = 4 \] Using the formula for the maximum value: \[ \text{Maximum value} = \sqrt{a^2 + b^2} \] \[ = \sqrt{3^2 + 4^2} \] \[ = \sqrt{9 + 16} \] \[ = \sqrt{25} \] \[ = 5 \] Step 4: Final Answer:
The maximum value of the expression $3 \cos\theta + 4 \sin\theta$ is 5. Therefore, option (C) is the correct answer.
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