Question

The mass of sodium acetate (CH₃COONa) required to prepare 250 mL of 0.35 M aqueous solution is g. (Molar mass of CH₃COONa is 82.02 g/mol)

Answer 1

Correct Answer: 7

Step 1 Determine moles via the formula:
Moles = Molarity × Volume (L)
Moles\(= 0.35 × 0.25=0.0875 mol\)

Step 2 Compute the mass of sodium acetate:
Mass = moles × molar mass
Mass\(= 0.35 × 0.25 × 82.02 = 7.18 g≈ 7 g\)