Question:medium

The locus of z satisfying the inequality $ \left| \frac{z+2i}{2z+i} \right| < 1 $, where $ z = x + iy $, is

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$|z-a|<|z-b|$ represents a half-plane or circle depending on the coefficients of $z$.

Updated On: Apr 10, 2026

$x^{2}+y^{2}<1$
$x^{2}-y^{2}<1$
$x^{2}+y^{2}>1$
$2x^{2}+3y^{2}<1$

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The Correct Option is C

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Questions Asked in MET exam

If $f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}$, then

MET - 2019
Continuity

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