Question:medium

The locus of centre of circles which cut orthogonally the circle \(x^2 + y^2 - 4x + 8 = 0\) and touches \(x + 1 = 0\), is

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Orthogonal condition + distance = radius → directly leads to locus equation.

Updated On: Apr 16, 2026

\(y^2 + 6x + 7 = 0\)
\(x^2 + y^2 + 2x + 3 = 0\)
\(x^2 + 3y + 4 = 0\)
None of the above

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The Correct Option is A

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The locus of centre of circles which cut orthogonally the circle \(x^2 + y^2 - 4x + 8 = 0\) and touches \(x + 1 = 0\), is

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The Correct Option is A

Solution and Explanation

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