Question:medium

The locus of centre of a circle which passes through the origin and cuts off a length of 4 unit from the line $x=3$ is

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Use the geometric relation $R^2 = p^2 + (L/2)^2$ where $p$ is perpendicular distance to a line and $L$ is chord length.
Updated On: Apr 10, 2026
  • $y^2+6x=0$
  • $y^2+6x=13$
  • $y^2+6x=10$
  • $x^2+6y=13$
Show Solution

The Correct Option is B

Solution and Explanation

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