Question:medium

The lines $\frac{x-3}{1} = \frac{y-2}{1} = \frac{z-5}{-k}$ and $\frac{x-4}{k} = \frac{y-3}{1} = \frac{z-3}{2}$ are coplanar, hence $k =$}

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Coplanar lines must satisfy $|(x_2-x_1) \cdot (d_1 \times d_2)| = 0$.
Updated On: May 12, 2026
  • $1, 2$
  • $-2, 3$
  • $-1, 2$
  • $\frac{1}{2}, 1$
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The Correct Option is C

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