Question

Two lines:
L₁: \(x = 5, \; \frac{y}{3 - \alpha} = \frac{z}{-2}\)

L₂: \(x = \alpha, \; \frac{y}{-1} = \frac{z}{2 - \alpha}\)

are coplanar. Then \(\alpha\) can take value(s):

• A. \(1,4,5\)
• B. \(1,2,5\)
• C. \(3,4,5\)
• D. 2,4,5

Hint:

Two lines are coplanar if the scalar triple product is zero.

Answer 1

The Correct Option is B