Question:medium

Two lines \(L_1:\;x=5,\; \dfrac{y}{3-\alpha}=\dfrac{z}{-2}\) \(L_2:\;x=\alpha,\; \dfrac{y}{1}=\dfrac{z}{2-\alpha}\) are coplanar. Then \(\alpha\) can take value(s)

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Use scalar triple product for coplanarity.

Updated On: Mar 23, 2026

\(1,4,5\)
\(1,2,5\)
\(3,4,5\)
\(2,4,5\)

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The Correct Option is B

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