Question:medium

The light ray is incident at angle of $60^{\circ}$ on a prism of angle $45^{\circ}$. When the light rays falls on the other surface at $90^{\circ}$, the refractive index of the material of prism $\mu$ and the angle of deviation $\delta$ are given by

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When a ray emerges normally, $e = 0$ and $r_2 = 0$.
Updated On: Apr 8, 2026
  • $\mu = \sqrt{2},\delta = 30^{\circ}$
  • $\mu = 1.5,\delta = 15^{\circ}$
  • $\mu = \frac{\sqrt{3}}{2},\delta = 30^{\circ}$
  • $\mu = \sqrt{\frac{3}{2}},\delta = 15^{\circ}$
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The Correct Option is D

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