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The length of a seconds pendulum if it is placed at height \(2R\) from the surface of the earth (R: radius of earth) is \(\frac{10}{xπ^2}\) \(m\). Find \(x\)
The length of a seconds pendulum if it is placed at height \(2R\) from the surface of the earth (R: radius of earth) is \(\frac{10}{xπ^2}\) \(m\). Find \(x\)
Updated On: Jan 13, 2026
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Solution and Explanation
The correct answer is 9
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