Question

The kinetic energy of translation of the molecules in 50 g of CO\(_2\) gas at 17°C is:

• A. 4102.8 J
• B. 4205.5 J
• C. 3986.3 J
• D. 3582.7 J

Hint:

Use the ideal gas law relations to compute kinetic energy in gas molecules.

Answer 1

The Correct Option is A

• Translational kinetic energy is calculated as: \[ (KE)_{{translational}} = \left[ \frac{3}{2} kT \right] \times \text{No. of molecules} \]
• The number of molecules is: \[ \frac{50}{44} \times 6.023 \times 10^{23} \]
• The resulting translational kinetic energy is: \[ (KE)_{{translational}} = 4108.644 \, \text{J} \]