Question

The IUPAC nomenclature of an element with electronic configuration $[ Rn ] 5 f ^{14} 6 d ^1 7 s ^2$ is :

• A. Unnilbium
• B. Unnilunium
• C. Unnilquadium
• D. Unniltrium

Answer 1

The Correct Option is D

To determine the IUPAC nomenclature of an element with the electronic configuration \([ \text{Rn} ] 5f^{14} 6d^1 7s^2\), let's analyze it step-by-step:

1. Identify the Element:
   • This electronic configuration represents an atom where the outermost electrons are situated in the \(7s\) and \(6d\) orbitals.
   • With \(5f^{14}\), \(6d^1\), and \(7s^2\) contributions, this configuration aligns with the element Lawrencium (Lr), which is the element with atomic number 103.
2. IUPAC Nomenclature:
   • The temporary systematic name for an element is based on its atomic number using Latin/Greek roots. For atomic number 103:
   • '1' is 'Un', '0' is 'nil', and '3' is 'trium'.
   • Thus, the name becomes Un-nil-trium with the systematic temporary name \(\text{Unniltrium (Unt)}\).
3. Evaluate Options:
   • Comparing with the given options:
     • Unnilbium (incorrect)
     • Unnilunium (incorrect)
     • Unnilquadium (incorrect)
     • Unniltrium (correct)
4. Conclusion:

The IUPAC nomenclature for the element with this configuration is correctly given by the option: Unniltrium.