Question:medium

Identify A in the following reaction.

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Strong oxidation with \(KMnO_4\) converts any alkyl chain (with at least one benzylic hydrogen) directly to Benzoic Acid (\(-COOH\)), regardless of chain length.
Updated On: Mar 16, 2026
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The Correct Option is B

Solution and Explanation

To identify compound A in the given reaction, let's analyze the processes involved:

The reaction shows compound A undergoing two separate transformations:

  1. Hydrogenation with 2H_2 in the presence of a platinum catalyst (Pt).
  2. Oxidation with potassium permanganate (KMnO_4) under heating.

First, let's break down these reactions:

1. Hydrogenation Reaction

In hydrogenation, alkenes are converted to alkanes. Therefore, compound A should contain an alkene group that is converted to a cyclic alkane in the product shown.

2. Oxidation Reaction with KMnO4

This reaction is typical for alkenes, where the double bond is oxidatively cleaved to form carboxylic acids. The product indicates two separate carboxylic acid chains, suggesting that compound A is a cyclic diene.

Based on these transformations, compound A must be a cycloalkene that, when hydrogenated, yields a cycloalkane, and when oxidized, yields carboxylic acids.

The correct structure for compound A is therefore:

This structure fulfills the requirement of having a double bond for hydrogenation and oxidation reactions, resulting in the observed products.

Conclusion

Compound A is correctly identified from the given options as the structure that aligns with the described chemical transformations in both reactions.

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