Question:medium

The integrating factor of $x \cdot \frac{dy}{dx} + y \log x = x \cdot e^x x^{-1/2} \log x$ is

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$\int \frac{\log x}{x} dx = \frac{(\log x)^2}{2}$.
Updated On: May 12, 2026
  • $(\log x)^x$
  • $x^{\log x}$
  • $(\sqrt{x})^{\log x}$
  • $e^{\sqrt{x} \log x}$
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The Correct Option is C

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