Question:medium

The integrating factor of the differential equation \((1 + x^{2})dy = (1 - 2xy)dx\) is

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For linear DE \(\frac{dy}{dx} + P(x)y = Q(x)\), IF = \(e^{\int P(x)dx}\).
Updated On: Apr 24, 2026
  • \(x^{2} + 1\)
  • \(\log_{e}(x^{2} + 1)\)
  • \(\frac{x}{x^{2} + 1}\)
  • \(x(x^{2} + 1)\)
  • \(\log_{e}|x|\)
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The Correct Option is A

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