
To find the gravitational field due to the 'left over part' of a uniform sphere, from which a smaller part has been removed, we can analyze the situation using the concept of superposition. The complete sphere of mass \(M\) generates a certain gravitational field at point \(P\), and the removed part generates another gravitational field at \(P\). The gravitational field at any point is a vector sum, hence it can be calculated by subtracting the gravitational effect of the removed part from the complete sphere.
Thus, the gravitational field at point \(P\), due to the 'left over part' of the sphere, is \(\frac{7}{8} \frac{GM}{x^2}\), which matches the given correct answer.
The height from Earth's surface at which acceleration due to gravity becomes \(\frac{g}{4}\) is \(\_\_\)? (Where \(g\) is the acceleration due to gravity on the surface of the Earth and \(R\) is the radius of the Earth.)