Question:medium

The general solution of the equation \(\tan^2x=1\) is

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When \(\tan x=\pm 1\), the general solution is \(x=n\pi\pm\frac{\pi}{4}\).
  • \(n\pi+\frac{\pi}{4}\) only
  • \(n\pi\pm\frac{\pi}{4}\)
  • \(2n\pi\pm\frac{\pi}{4}\)
  • \(n\pi-\frac{\pi}{4}\) only
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
We need to find the general solution for a trigonometric equation involving the square of the tangent function. This requires using the standard formula for general solutions of this type.
Step 2: Key Formula or Approach:
The general solution for an equation of the form $\tan^2 x = \tan^2 \alpha$ is given by: \[ x = n\pi \pm \alpha \] where n is any integer.
Step 3: Detailed Explanation:
The given equation is: \[ \tan^2 x = 1 \] We need to find an angle $\alpha$ such that $\tan^2 \alpha = 1$. We know that $\tan(\frac{\pi}{4}) = 1$. Therefore, $\tan^2(\frac{\pi}{4}) = (1)^2 = 1$. So, we can write the equation as: \[ \tan^2 x = \tan^2\left(\frac{\pi}{4}\right) \] This is now in the form $\tan^2 x = \tan^2 \alpha$, with $\alpha = \frac{\pi}{4}$. Using the general solution formula from Step 2: \[ x = n\pi \pm \frac{\pi}{4} \] where n is any integer.
Step 4: Final Answer:
The general solution for the given equation is $x = n\pi \pm \frac{\pi}{4}$. Therefore, option (B) is correct.
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