Step 1: Cyclic Polymerization.
The initial substance undergoes cyclic polymerization, forming a cyclic precursor for subsequent reactions.
Step 2: Gatterman-Koch's Reaction.
This reaction introduces a formyl group to an aromatic compound, a crucial intermediate step.
Step 3: Pomeranz-Fritsch's Reaction.
This reaction converts the intermediate from Step 2 into isoquinoline.
Step 4: Conclusion.
The correct sequence is cyclic polymerization, Gatterman-Koch's reaction, and Pomeranz-Fritsch's reaction. Therefore, option (4) is correct.
Final Answer: \[\boxed{\text{(4) (i) Cyclic polymerization, (ii) Gatterman-Koch's reaction, (iii) Pomeranz-Fritsch's reaction}}\]
Which of the following amino compound(s) CANNOT be prepared by Gabriel phthalimide synthesis?
(A) n-Butylamine
(B) Alanine
(C) Aniline
(D) t-Butylamine
Choose the correct answer from the options given below:
The final product (D) in the above sequential reaction is:

The reaction is carried out by:
