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The oxymurcuration-demercuration sequence involves hydration of alkenes using mercuric acetate followed by reduction with sodium borohydride.
Updated On: Feb 10, 2026
  • (I) KOH (alc.), (II) oxymurcuration-demercuration
  • (I) KOH (aq.), (II) Conc. H\(_2\)SO\(_4\)
  • (I) KOH (alc.), (II) Hydroboration-oxidation
  • (I) Nucleophilic addition-elimination, (II) oxymurcuration-demercuration
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The Correct Option is A

Solution and Explanation

Step 1: KOH (alc.). Potassium hydroxide in alcohol (KOH (alc.)) causes elimination of the bromine atom, resulting in the formation of an alkene.

Step 2: Oxymurcuration-demercuration. The alkene subsequently undergoes oxymurcuration-demercuration, yielding an alcohol at the original site of bromine attachment. Therefore, option (1) is correct.

Final Answer: \[ \boxed{\text{(1) (I) KOH (alc.), (II) oxymurcuration-demercuration}} \]

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