Step 1: Kolbe Electrolysis.
Kolbe's electrolysis of esters, such as ethyl propionate, results in the formation of alkanes through decarboxylation of two ester molecules at the anode. Ethylene is not produced because it is an unsaturated compound, and Kolbe's electrolysis primarily generates saturated alkanes.
Step 2: Alkanes Formed.
Decarboxylation of the ester during electrolysis yields products like n-butane, n-propane, and ethane. Ethylene is not among these products.
Step 3: Conclusion.
Therefore, ethylene is not generated during the Kolbe electrolysis of ethyl propionate. The correct identification of the substance not formed is (3) Ethylene.
Final Answer: \[\boxed{\text{(3) Ethylene}}\]
Which of the following amino compound(s) CANNOT be prepared by Gabriel phthalimide synthesis?
(A) n-Butylamine
(B) Alanine
(C) Aniline
(D) t-Butylamine
Choose the correct answer from the options given below:

Above conversion is carried out using:
The reaction is carried out by:
