Question:medium

The equation of the parabola whose vertex is (-1, -2), axis is vertical and which passes through the point (3, 6), is

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For vertical axis parabola: \((x - h)^2 = 4a(y - k)\), opens upward if \(a>0\).
Updated On: Apr 7, 2026
  • \(x^2 + 2x - 2y - 3 = 0\)
  • \(2x^2 = 3y\)
  • \(x^2 - 2x + 2y - 3 = 0\)
  • \(x^2 - 2x - 2y - 3 = 0\)
Show Solution

The Correct Option is A

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