Question:medium

The equation of the circle which passes through the origin and cuts orthogonally each of the circles $ x^{2} + y^{2} - 6x + 8 = 0 $ and $ x^{2} + y^{2} - 2x - 2y = 7 $ is

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Orthogonality condition: $2g_{1}g_{2} + 2f_{1}f_{2} = c_{1} + c_{2}$.

Updated On: Apr 10, 2026

$3x^{2}+3y^{2}-8x-13y=0$
$3x^{2}+3y^{2}-8x+29y=0$
$3x^{2}+3y^{2}+8x+29y=0$
$3x^{2}+3y^{2}-8x-29y=0$

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The Correct Option is B

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The equation of the circle which passes through the origin and cuts orthogonally each of the circles \( x^{2} + y^{2} - 6x + 8 = 0 \) and \( x^{2} + y^{2} - 2x - 2y = 7 \) is

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The Correct Option is B

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