Question:medium

The electric potential is +100 V at a distance of 10 cm from a point charge \(q\). Then, \(q\) is equal to

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\(V = \dfrac{kq}{r}\) where \(k = 9 \times 10^9\) N m\(^2\) C\(^{-2}\). Positive \(V\) implies positive charge.
Updated On: Apr 8, 2026
  • \(+1.1 \times 10^{-9}\) C
  • \(+1.1 \times 10^{-3}\) C
  • 3 C
  • \(3 \times 10^{-9}\) C
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The Correct Option is A

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