Question:easy

The electric field strength at a point in an electric field is $30\,N/C$. Find the force experienced by a charge of $20\,C$ at that point.

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Remember the relation: \[ F=qE \] Force is directly proportional to both charge and electric field strength.
Updated On: Jun 8, 2026
  • $600\,N$
  • $30\,N$
  • $20\,N$
  • $300\,N$
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Recall what electric field means.
The electric field $E$ at a point tells us the force felt by each unit of charge placed there. By definition $E=\frac{F}{q}$. We use this because the field and the charge are given and the force is asked.

Step 2: Rearrange for force.
Multiply both sides by $q$ to make the force the subject. \[ F=qE \] This says: stronger field or bigger charge gives a bigger force.

Step 3: Write the given data.
The field is $E=30\,\text{N/C}$ and the charge is $q=20\,\text{C}$.

Step 4: Substitute the values.
Put both numbers into $F=qE$. \[ F=20\times 30 \]

Step 5: Do the multiplication.
Multiply carefully. \[ F=600\,\text{N} \]

Step 6: State the answer.
The charge feels a force of $600\,\text{N}$, which is option 1. The other choices come from forgetting to multiply both numbers together. \[ \boxed{600\ \text{N}} \]
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